9x^2-112x+348=0

Solution for 9x^2-112x+348=0 equation:

9x^2-112x+348=0

a = 9; b = -112; c = +348;
Δ = b2-4ac
Δ = -1122-4·9·348
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-4}{2*9}=\frac{108}{18}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+4}{2*9}=\frac{116}{18}
=6+4/9
$